4x^2+x-(1/8)=0

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Solution for 4x^2+x-(1/8)=0 equation: 


x in (-oo:+oo)

4*x^2+x-(1/8) = 0

4*x^2+x-1/8 = 0

4*x^2+x-1/8 = 0

DELTA = 1^2-(-1/8*4*4)

DELTA = 3

DELTA > 0

x = (3^(1/2)-1)/(2*4) or x = (-3^(1/2)-1)/(2*4)

x = (3^(1/2)-1)/8 or x = (-(3^(1/2)+1))/8

x in { (-(3^(1/2)+1))/8, (3^(1/2)-1)/8 }

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